Q:

3. Write the slope-intercept form of the equation of the line described.a. Point= (1,-1), parallel to y=-6x+1b. Point= (4,5), parallel to y=1/2x+34. Write the standard from of the equation of the line through the given point with the given slope.a. Point=(-4,4), Slope= -7/4b. Point=(1,2), Slope= 65. Write the equation of the line.a. Point= (-3,3), parallel to y=0b. Point= (5,-2), perpendicular to x=0

Accepted Solution

A:
Answer:5b. y = βˆ’25a. y = 34b. βˆ’6x + y = βˆ’44a. 7x + 4y = βˆ’123b. y = Β½x + 33a. y = βˆ’6x + 5Step-by-step explanation:5.b. y = βˆ’2a. y = 3* Perpendicular Lines have OPPOSITE MULTIPLICATIVE INVERSE RATE OF CHANGES [SLOPES], but in this case, since the slope is undefined [5b], we just take the y-coordinate of the ordered pair.* Parallel lines have SIMILAR RATE OF CHANGES [SLOPES], but in this case, since the slope is zero [5a], we just take the y-coordinate of the ordered pair.__________________________________________________________4.Plug the coordinates into the Slope-Intercept Formula first, then convert to Standard Form [Ax + By = C]:b.2 = 6[1] + b 6βˆ’4 = by = 6x - 4-6x - 6x_________βˆ’6x + y = βˆ’4 >> Standard Equationa.4 = βˆ’7⁄4[-4] + b 7βˆ’3 = by = βˆ’7⁄4x - 3+7⁄4x +7⁄4x____________7⁄4x + y = βˆ’3 [We do not want fractions in our Standard Equation, so multiply by the denominator to get rid of it.]4[7⁄4x + y = βˆ’3]7x + 4y = βˆ’12 >> Standard Equation* 1ΒΎ = 7⁄4__________________________________________________________3.Plug both coordinates into the Slope-Intercept Formula:b.5 = Β½[4] + b 23 = by = Β½x + 3 >> EXACT SAME EQUATIONa.βˆ’1 = βˆ’6[1] + b βˆ’65 = by = βˆ’6x + 5* Parallel lines have SIMILAR RATE OF CHANGES [SLOPES].I am joyous to assist you anytime.