Answer:Q16.Quadrant II is (- , +)I choose the point (-1, 1) and the slope 1.Substitute point and slope into the formula to find b.y = mx + b1 = (1)(-1) + bb = 2The equation is y = x + 2Q15.The slope is represented by the m value in y=mx+b. Choose a random negative value for m. I will make b 0 so I don't need to write it.y= -x (slope is negative 1)Q14.m = 5; (-6,1)Sub m and point into y=mx+b; isolate for b.y=mx+b1=5(-6)+b1 = -30 + bb = 31Sub b=31 and m=5 into equation of a lineThe equation is y = 5x + 31Q13.Find slope:Choose points (0, 8) and (1, 10)m = (y2-y1)/(x2-x1) = (10-8)/(1-0) = 2/1 = 2Find b by substituting slope and point (0,8) into equation of a liney=mx+b8=2(0)+b8 = 2 + bb = 6Sub b=6 and m=2 into y=mx+bThe equation of the line is y=2x+6Q12.Find slope between (5,2) and (6,4)m = (y2-y1)/(x2-x1) = (4-2)/(6-5) = 2/1 = 2Find b by substituting slope and point (5,2) into equation of a liney=mx+b2 = 2(5) + b2 = 10 + bb = -8Sub b= -8 and m=2 to find equationThe equation of the line is y=2x-8Q11.Sub m= -4 and point (5,9) into the equation of a line, isolate by=mx+b9 = -4(5) + b9 = -20 + bb = 29Sub b=29 and m= -4 into the equation of a lineThe equation of a line is y = -4x + 29