Answer:[tex]\large\boxed{(x^2+4x+8)(2x-1)=2x^3+7x^2+12x-8}[/tex]Step-by-step explanation:Use FOIL: (a + b)(c + d) = ac + ad + bc + bd[tex](x^2+4x+8)(2x-1)\\\\=(x^2)(2x)+(x^2)(-1)+(4x)(2x)+(4x)(-1)+(8)(2x)+(8)(-1)\\\\=2x^3-x^2+8x^2-4x+16x-8\qquad\text{combine like terms}\\\\=2x^3+(-x^2+8x^2)+(-4x+16x)-8\\\\=2x^3+7x^2+12x-8[/tex]