MATH SOLVE

3 months ago

Q:
# Your utility company charges 14 cents per kilowatt-hour of electricity. Complete parts (a) and (b) below.a. What is the daily cost of keeping lit a 1001-watt light bulb for 12hours each day?b. How much will you save in a year if you replace the bulb with an LED bulb that provides the same amount of light using only 10 watts of power?

Accepted Solution

A:

Answer:The daily cost of the bulb is US$ 1.68 and I'll save US$ 607.07 annually if I replace the bulb with and LED bulbStep-by-step explanation:Cost of kilowatt-hour of electricity = US$ 0.14 for 1,000 wattsPart A. What is the daily cost of keeping lit a 1001-watt light bulb for 12 hours each day? And for solving part B, we should calculate the annual cost as well.Daily cost of the bulb = Cost of kilowatt-hour * Number of hours * electricity consumptionDaily cost of the bulb = 0.14 * 12 * 1.001Daily cost of the bulb = US$ 1.68 (Rounding to two decimal places)Annual cost of this bulb = Daily cost * 365Annual cost of this bulb = 1.68 * 365Annual cost of this bulb = US$ 613.20Part B. How much will you save in a year if you replace the bulb with an LED bulb that provides the same amount of light using only 10 watts of power?Daily cost of the bulb = Cost of kilowatt-hour * Number of hours * electricity consumptionDaily cost of the bulb = 0.14 * 12 * 0.01 (Consumption = 10/1,000)Daily cost of the bulb = 0.0168Annual cost of the bulb = Daily cost * 365Annual cost of the bulb = 0.0168 * 365Annual cost of the bulb = US$ 6.13 (Rounding to two decimal places)Savings = Cost of the first bulb in part A - Cost of the second bulb in part BSavings = 613.20 - 6.13Savings = US$ 607.07